$$(\begin{matrix}6&4\\ 4&7\end{matrix})(\begin{matrix}2\\ 1\end{matrix})$$
$\left(\begin{matrix}16\\15\end{matrix}\right)$
$$\left(\begin{matrix}6&4\\4&7\end{matrix}\right)\left(\begin{matrix}2\\1\end{matrix}\right)$$
$$\left(\begin{matrix}6\times 2+4\\\end{matrix}\right)$$
$$\left(\begin{matrix}6\times 2+4\\4\times 2+7\end{matrix}\right)$$
$$\left(\begin{matrix}12+4\\8+7\end{matrix}\right)$$
$$\left(\begin{matrix}16\\15\end{matrix}\right)$$
Show Solution
Hide Solution
$\left(\begin{matrix}16&15\end{matrix}\right)$