How to solve (B-(3)^(3))=

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (B-(3)^(3))= | Equatix

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

Question

$$(B- { 3 }^{ 3 } )=$$

Differentiate w.r.t. B

$1$

Steps Using Derivative Rule for Sum

Calculate $3$ to the power of $3$ and get $27$.

$$\frac{\mathrm{d}}{\mathrm{d}B}(B-27)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is $0$. The derivative of $ax^{n}$ is $nax^{n-1}$.

$$B^{1-1}$$

Subtract $1$ from $1$.

$$B^{0}$$

For any term $t$ except $0$, $t^{0}=1$.

$$1$$

Show Solution

Evaluate

$B-27$

Show Solution

Example

Question

Differentiate w.r.t. B

Steps Using Derivative Rule for Sum

Evaluate

Solution Steps