Question

$$( \cup + \cup ) \times i=100$$

Answer

u=5*sqrt(2*IM)*IM,-5*sqrt(2*IM)*IM

Solution


Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[({u}^{2}+{u}^{2})\imath =100\]
Simplify  \({u}^{2}+{u}^{2}\)  to  \(2{u}^{2}\).
\[2{u}^{2}\imath =100\]
Regroup terms.
\[2\imath {u}^{2}=100\]
Divide both sides by \(2\).
\[\imath {u}^{2}=\frac{100}{2}\]
Simplify  \(\frac{100}{2}\)  to  \(50\).
\[\imath {u}^{2}=50\]
Divide both sides by \(\imath \).
\[{u}^{2}=\frac{50}{\imath }\]
Rationalize the denominator: \(\frac{50}{\imath } \cdot \frac{\imath }{\imath }=-50\imath \).
\[{u}^{2}=-50\imath \]
Take the square root of both sides.
\[u=\pm \sqrt{-50\imath }\]
Simplify  \(\sqrt{-50\imath }\)  to  \(\sqrt{50\imath }\imath \).
\[u=\pm \sqrt{50\imath }\imath \]
Use this rule: \(\sqrt{ab}=\sqrt{a}\sqrt{b}\).
\[u=\pm \sqrt{50}\sqrt{\imath }\imath \]
Simplify  \(\sqrt{50}\)  to  \(5\sqrt{2}\).
\[u=\pm 5\sqrt{2}\sqrt{\imath }\imath \]
Simplify  \(5\sqrt{2}\sqrt{\imath }\imath \)  to  \(5\sqrt{2\imath }\imath \).
\[u=\pm 5\sqrt{2\imath }\imath \]