$$( { 2 }^{ 2 } +21+ { 1 }^{ 2 } ) \times ( { 2 }^{ 2 } -21+ { 1 }^{ 2 } )$$
$-416$
$$\left(4+21+1^{2}\right)\left(2^{2}-21+1^{2}\right)$$
$$\left(25+1^{2}\right)\left(2^{2}-21+1^{2}\right)$$
$$\left(25+1\right)\left(2^{2}-21+1^{2}\right)$$
$$26\left(2^{2}-21+1^{2}\right)$$
$$26\left(4-21+1^{2}\right)$$
$$26\left(-17+1^{2}\right)$$
$$26\left(-17+1\right)$$
$$26\left(-16\right)$$
$$-416$$
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