$$( { 4 }^{ 2 } +5)+ { 2 }^{ 3 } +4+(2(4)-5)$$
$36$
$$16+5+2^{3}+4+2\times 4-5$$
$$21+2^{3}+4+2\times 4-5$$
$$21+8+4+2\times 4-5$$
$$29+4+2\times 4-5$$
$$33+2\times 4-5$$
$$33+8-5$$
$$41-5$$
$$36$$
Show Solution
Hide Solution
$2^{2}\times 3^{2}$