Question

$$( { x }^{ 2 } -10x+16)( { x }^{ 2 } -4x-32)=0$$

Answer

x=8,2,-4

Solution


Factor \({x}^{2}-10x+16\).
\[(x-8)(x-2)({x}^{2}-4x-32)=0\]
Factor \({x}^{2}-4x-32\).
\[(x-8)(x-2)(x-8)(x+4)=0\]
Solve for \(x\).
\[x=8,2,-4\]