Question

$$( { x }^{ 2 } -3x+2)( { x }^{ 2 } +6x+8)=0$$

Answer

x=2,1,-2,-4

Solution


Factor \({x}^{2}-3x+2\).
\[(x-2)(x-1)({x}^{2}+6x+8)=0\]
Factor \({x}^{2}+6x+8\).
\[(x-2)(x-1)(x+2)(x+4)=0\]
Solve for \(x\).
\[x=1,-4,\pm 2\]