Solve ((x)^(2)-3x+2)+4\times(2x+1)-(3(x)^(2)+4x-1) | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$( { x }^{ 2 } -3x+2)+4 \times (2x+1)-(3 { x }^{ 2 } +4x-1)$$

Evaluate

$7+x-2x^{2}$

Solution Steps

Use the distributive property to multiply $4$ by $2x+1$.

$$x^{2}-3x+2+8x+4-\left(3x^{2}+4x-1\right)$$

Combine $-3x$ and $8x$ to get $5x$.

$$x^{2}+5x+2+4-\left(3x^{2}+4x-1\right)$$

Add $2$ and $4$ to get $6$.

$$x^{2}+5x+6-\left(3x^{2}+4x-1\right)$$

To find the opposite of $3x^{2}+4x-1$, find the opposite of each term.

$$x^{2}+5x+6-3x^{2}-4x+1$$

Combine $x^{2}$ and $-3x^{2}$ to get $-2x^{2}$.

$$-2x^{2}+5x+6-4x+1$$

Combine $5x$ and $-4x$ to get $x$.

$$-2x^{2}+x+6+1$$

Add $6$ and $1$ to get $7$.

$$-2x^{2}+x+7$$

Expand

$7+x-2x^{2}$

Solution Steps

Use the distributive property to multiply $4$ by $2x+1$.

$$x^{2}-3x+2+8x+4-\left(3x^{2}+4x-1\right)$$

Combine $-3x$ and $8x$ to get $5x$.

$$x^{2}+5x+2+4-\left(3x^{2}+4x-1\right)$$

Add $2$ and $4$ to get $6$.

$$x^{2}+5x+6-\left(3x^{2}+4x-1\right)$$

To find the opposite of $3x^{2}+4x-1$, find the opposite of each term.

$$x^{2}+5x+6-3x^{2}-4x+1$$

Combine $x^{2}$ and $-3x^{2}$ to get $-2x^{2}$.

$$-2x^{2}+5x+6-4x+1$$

Combine $5x$ and $-4x$ to get $x$.

$$-2x^{2}+x+6+1$$

Add $6$ and $1$ to get $7$.

$$-2x^{2}+x+7$$