Question

$$( { x }^{ 2 } +7x+12)( { x }^{ 2 } -8x+15)=0$$

Answer

x=-3,-4,5,3

Solution


Factor \({x}^{2}+7x+12\).
\[(x+3)(x+4)({x}^{2}-8x+15)=0\]
Factor \({x}^{2}-8x+15\).
\[(x+3)(x+4)(x-5)(x-3)=0\]
Solve for \(x\).
\[x=-4,5,\pm 3\]