$$(d1)y= \frac{ 2 }{ 3 } x+4$$
$\left\{\begin{matrix}d_{1}=\frac{2\left(x+6\right)}{3y}\text{, }&y\neq 0\\d_{1}\in \mathrm{C}\text{, }&x=-6\text{ and }y=0\end{matrix}\right.$
$\left\{\begin{matrix}d_{1}=\frac{2\left(x+6\right)}{3y}\text{, }&y\neq 0\\d_{1}\in \mathrm{R}\text{, }&x=-6\text{ and }y=0\end{matrix}\right.$
$x=\frac{3\left(d_{1}y-4\right)}{2}$
