$$(\frac{0}{3}-\frac{4}{5})\cdot\frac{3}{\frac{2}{3}+\frac{4}{5}}}$$
$-\frac{18}{11}\approx -1.636363636$
$$\left(0-\frac{4}{5}\right)\times \frac{3}{\frac{2}{3}+\frac{4}{5}}$$
$$-\frac{4}{5}\times \frac{3}{\frac{2}{3}+\frac{4}{5}}$$
$$-\frac{4}{5}\times \frac{3}{\frac{10}{15}+\frac{12}{15}}$$
$$-\frac{4}{5}\times \frac{3}{\frac{10+12}{15}}$$
$$-\frac{4}{5}\times \frac{3}{\frac{22}{15}}$$
$$-\frac{4}{5}\times 3\times \frac{15}{22}$$
$$-\frac{4}{5}\times \frac{3\times 15}{22}$$
$$-\frac{4}{5}\times \frac{45}{22}$$
$$\frac{-4\times 45}{5\times 22}$$
$$\frac{-180}{110}$$
$$-\frac{18}{11}$$
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$-\frac{18}{11} = -1\frac{7}{11} = -1.6363636363636365$
