$$(\frac{1}{2}a+\frac{2}{3}b)^{2})$$
$\frac{\left(3a+4b\right)^{2}}{36}$
$$\frac{1}{4}a^{2}+\frac{2}{3}ab+\frac{4}{9}b^{2}$$
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$\frac{2ab}{3}+\frac{4b^{2}}{9}+\frac{a^{2}}{4}$
