$$(\frac{1}{2})^{2}-4(\frac{1}{2})^{2}+\frac{1}{2}-2$$
$-\frac{9}{4}=-2.25$
$$\frac{1}{4}-4\times \left(\frac{1}{2}\right)^{2}+\frac{1}{2}-2$$
$$\frac{1}{4}-4\times \frac{1}{4}+\frac{1}{2}-2$$
$$\frac{1}{4}-1+\frac{1}{2}-2$$
$$\frac{1}{4}-\frac{4}{4}+\frac{1}{2}-2$$
$$\frac{1-4}{4}+\frac{1}{2}-2$$
$$-\frac{3}{4}+\frac{1}{2}-2$$
$$-\frac{3}{4}+\frac{2}{4}-2$$
$$\frac{-3+2}{4}-2$$
$$-\frac{1}{4}-2$$
$$-\frac{1}{4}-\frac{8}{4}$$
$$\frac{-1-8}{4}$$
$$-\frac{9}{4}$$
Show Solution
Hide Solution
$-\frac{9}{4} = -2\frac{1}{4} = -2.25$
