$$(\frac{1}{3})^{-2}+(\frac{1}{2})^{-2}+(\frac{1}{4})^{-2}$$
$29$
$$9+\left(\frac{1}{2}\right)^{-2}+\left(\frac{1}{4}\right)^{-2}$$
$$9+4+\left(\frac{1}{4}\right)^{-2}$$
$$13+\left(\frac{1}{4}\right)^{-2}$$
$$13+16$$
$$29$$
Show Solution
Hide Solution