$$(\frac{1}{4})^{+2}+[\frac{-1}{2}]^{3}$$
$-\frac{1}{16}=-0.0625$
$$\frac{1}{16}+\left(\frac{-1}{2}\right)^{3}$$
$$\frac{1}{16}+\left(-\frac{1}{2}\right)^{3}$$
$$\frac{1}{16}-\frac{1}{8}$$
$$-\frac{1}{16}$$
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$-\frac{1}{16} = -0.0625$
