Question

$$(\frac{1}{81})^{\triangle}=\frac{1}{3^{8}}$$

Answer

$$t=log(181,13^8/(e*IM*r*a*n*g*l))$$

Solution


Regroup terms.
\[e\imath rangl\times {181}^{t}={13}^{8}\]
Divide both sides by \(e\).
\[\imath rangl\times {181}^{t}=\frac{{13}^{8}}{e}\]
Divide both sides by \(\imath \).
\[rangl\times {181}^{t}=\frac{\frac{{13}^{8}}{e}}{\imath }\]
Simplify  \(\frac{\frac{{13}^{8}}{e}}{\imath }\)  to  \(\frac{{13}^{8}}{e\imath }\).
\[rangl\times {181}^{t}=\frac{{13}^{8}}{e\imath }\]
Divide both sides by \(r\).
\[angl\times {181}^{t}=\frac{\frac{{13}^{8}}{e\imath }}{r}\]
Simplify  \(\frac{\frac{{13}^{8}}{e\imath }}{r}\)  to  \(\frac{{13}^{8}}{e\imath r}\).
\[angl\times {181}^{t}=\frac{{13}^{8}}{e\imath r}\]
Divide both sides by \(a\).
\[ngl\times {181}^{t}=\frac{\frac{{13}^{8}}{e\imath r}}{a}\]
Simplify  \(\frac{\frac{{13}^{8}}{e\imath r}}{a}\)  to  \(\frac{{13}^{8}}{e\imath ra}\).
\[ngl\times {181}^{t}=\frac{{13}^{8}}{e\imath ra}\]
Divide both sides by \(n\).
\[gl\times {181}^{t}=\frac{\frac{{13}^{8}}{e\imath ra}}{n}\]
Simplify  \(\frac{\frac{{13}^{8}}{e\imath ra}}{n}\)  to  \(\frac{{13}^{8}}{e\imath ran}\).
\[gl\times {181}^{t}=\frac{{13}^{8}}{e\imath ran}\]
Divide both sides by \(g\).
\[l\times {181}^{t}=\frac{\frac{{13}^{8}}{e\imath ran}}{g}\]
Simplify  \(\frac{\frac{{13}^{8}}{e\imath ran}}{g}\)  to  \(\frac{{13}^{8}}{e\imath rang}\).
\[l\times {181}^{t}=\frac{{13}^{8}}{e\imath rang}\]
Divide both sides by \(l\).
\[{181}^{t}=\frac{\frac{{13}^{8}}{e\imath rang}}{l}\]
Simplify  \(\frac{\frac{{13}^{8}}{e\imath rang}}{l}\)  to  \(\frac{{13}^{8}}{e\imath rangl}\).
\[{181}^{t}=\frac{{13}^{8}}{e\imath rangl}\]
Use Definition of Common Logarithm: \({b}^{a}=x\) if and only if \(log_b(x)=a\).
\[t=\log_{181}{(\frac{{13}^{8}}{e\imath rangl})}\]