$$( \frac { 10 } { 2 } + \frac { 3 b } { 4 } ) ( \frac { 2 } { 2 } + \frac { 3 b } { 4 } )$$
$\frac{9b^{2}}{16}+\frac{9b}{2}+5$
$$\left(\frac{10}{2}+\frac{3b}{4}\right)\left(1+\frac{3b}{4}\right)$$
$$\left(5+\frac{3b}{4}\right)\left(1+\frac{3b}{4}\right)$$
$$\left(\frac{5\times 4}{4}+\frac{3b}{4}\right)\left(1+\frac{3b}{4}\right)$$
$$\frac{5\times 4+3b}{4}\left(1+\frac{3b}{4}\right)$$
$$\frac{20+3b}{4}\left(1+\frac{3b}{4}\right)$$
$$\frac{20+3b}{4}\left(\frac{4}{4}+\frac{3b}{4}\right)$$
$$\frac{20+3b}{4}\times \frac{4+3b}{4}$$
$$\frac{\left(20+3b\right)\left(4+3b\right)}{4\times 4}$$
$$\frac{\left(20+3b\right)\left(4+3b\right)}{16}$$
$$\frac{80+60b+12b+9b^{2}}{16}$$
$$\frac{80+72b+9b^{2}}{16}$$
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