$$(\frac{11}{18}-\frac{4}{9})+\frac{y}{6}$$
$\frac{y+1}{6}$
$$\frac{11}{18}-\frac{8}{18}+\frac{y}{6}$$
$$\frac{11-8}{18}+\frac{y}{6}$$
$$\frac{3}{18}+\frac{y}{6}$$
$$\frac{1}{6}+\frac{y}{6}$$
$$\frac{1+y}{6}$$
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$$\frac{3+3y}{18}$$
$$3y+3$$
$$3\left(y+1\right)$$
$$\frac{y+1}{6}$$
