How to solve ( 18 32 )^ -3 2

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve ( 18 32 )^ -3 2 | Equatix

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$$(\frac{18}{32})^{-3}{2}}$$

$\frac{8192}{729}\approx 11.237311385$

Reduce the fraction $\frac{18}{32}$ to lowest terms by extracting and canceling out $2$.

$$\left(\frac{9}{16}\right)^{-3}\times 2$$

Calculate $\frac{9}{16}$ to the power of $-3$ and get $\frac{4096}{729}$.

$$\frac{4096}{729}\times 2$$

Multiply $\frac{4096}{729}$ and $2$ to get $\frac{8192}{729}$.

$$\frac{8192}{729}$$

$\frac{2 ^ {13}}{3 ^ {6}} = 11\frac{173}{729} = 11.237311385459533$