How to solve (18/32) ^ (- 3/2)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (18/32) ^ (- 3/2) | Equatix

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$$(\frac{18}{32})^{-3/2}$$

$\frac{64}{27}\approx 2.37037037$

Reduce the fraction $\frac{18}{32}$ to lowest terms by extracting and canceling out $2$.

$$\left(\frac{9}{16}\right)^{\frac{-3}{2}}$$

Fraction $\frac{-3}{2}$ can be rewritten as $-\frac{3}{2}$ by extracting the negative sign.

$$\left(\frac{9}{16}\right)^{-\frac{3}{2}}$$

Calculate $\frac{9}{16}$ to the power of $-\frac{3}{2}$ and get $\frac{64}{27}$.

$$\frac{64}{27}$$

$\frac{2 ^ {6}}{3 ^ {3}} = 2\frac{10}{27} = 2.3703703703703702$