Solve [((2)/(3)\div(4)/(3))+1] | Equatix

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Question

$$[( \frac{ 2 }{ 3 } \div \frac{ 4 }{ 3 } )+1]$$

$\frac{3}{2}=1.5$

Divide $\frac{2}{3}$ by $\frac{4}{3}$ by multiplying $\frac{2}{3}$ by the reciprocal of $\frac{4}{3}$.

$$\frac{2}{3}\times \frac{3}{4}+1$$

Multiply $\frac{2}{3}$ times $\frac{3}{4}$ by multiplying numerator times numerator and denominator times denominator.

$$\frac{2\times 3}{3\times 4}+1$$

Cancel out $3$ in both numerator and denominator.

$$\frac{2}{4}+1$$

Reduce the fraction $\frac{2}{4}$ to lowest terms by extracting and canceling out $2$.

$$\frac{1}{2}+1$$

Convert $1$ to fraction $\frac{2}{2}$.

$$\frac{1}{2}+\frac{2}{2}$$

Since $\frac{1}{2}$ and $\frac{2}{2}$ have the same denominator, add them by adding their numerators.

$$\frac{1+2}{2}$$

Add $1$ and $2$ to get $3$.

$$\frac{3}{2}$$

$\frac{3}{2} = 1\frac{1}{2} = 1.5$