Question

$$(\frac{2}{3})^{5}=\frac{2^{}}{3^{}}$$

Answer

$$x=23^(5/2)/sqrt(2^Bo*3^Bo),-23^(5/2)/sqrt(2^Bo*3^Bo)$$

Solution


Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[{23}^{5}={2}^{Bo}{x}^{2}\times {3}^{Bo}\]
Regroup terms.
\[{23}^{5}={2}^{Bo}\times {3}^{Bo}{x}^{2}\]
Divide both sides by \({2}^{Bo}\).
\[\frac{{23}^{5}}{{2}^{Bo}}={3}^{Bo}{x}^{2}\]
Divide both sides by \({3}^{Bo}\).
\[\frac{\frac{{23}^{5}}{{2}^{Bo}}}{{3}^{Bo}}={x}^{2}\]
Simplify  \(\frac{\frac{{23}^{5}}{{2}^{Bo}}}{{3}^{Bo}}\)  to  \(\frac{{23}^{5}}{{2}^{Bo}\times {3}^{Bo}}\).
\[\frac{{23}^{5}}{{2}^{Bo}\times {3}^{Bo}}={x}^{2}\]
Take the square root of both sides.
\[\pm \sqrt{\frac{{23}^{5}}{{2}^{Bo}\times {3}^{Bo}}}=x\]
Simplify  \(\sqrt{\frac{{23}^{5}}{{2}^{Bo}\times {3}^{Bo}}}\)  to  \(\frac{\sqrt{{23}^{5}}}{\sqrt{{2}^{Bo}\times {3}^{Bo}}}\).
\[\pm \frac{\sqrt{{23}^{5}}}{\sqrt{{2}^{Bo}\times {3}^{Bo}}}=x\]
Simplify  \(\sqrt{{23}^{5}}\)  to  \({({23}^{5})}^{\frac{1}{2}}\).
\[\pm \frac{{({23}^{5})}^{\frac{1}{2}}}{\sqrt{{2}^{Bo}\times {3}^{Bo}}}=x\]
Use this rule: \({({x}^{a})}^{b}={x}^{ab}\).
\[\pm \frac{{23}^{\frac{5}{2}}}{\sqrt{{2}^{Bo}\times {3}^{Bo}}}=x\]
Switch sides.
\[x=\pm \frac{{23}^{\frac{5}{2}}}{\sqrt{{2}^{Bo}\times {3}^{Bo}}}\]

Decimal Form: ±2536.994876