How to solve (2/3 + 2/6) ^ 1

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (2/3 + 2/6) ^ 1 | Equatix

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3(r+2s)=2t-4

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Question

$$(\frac{2}{3}+\frac{2}{6})^{1}.$$

Evaluate

$1$

Solution Steps

Reduce the fraction $\frac{2}{6}$ to lowest terms by extracting and canceling out $2$.

$$\left(\frac{2}{3}+\frac{1}{3}\right)^{1}$$

Add $\frac{2}{3}$ and $\frac{1}{3}$ to get $1$.

$$1^{1}$$

Calculate $1$ to the power of $1$ and get $1$.

$$1$$

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Factor

$1$

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