$$(\frac{2}{5}\times\frac{1}{2})+2-\frac{-11}{9}-\frac{-3}{2}$$
$\frac{443}{90}\approx 4.922222222$
$$\frac{2\times 1}{5\times 2}+2-\frac{-11}{9}-\frac{-3}{2}$$
$$\frac{1}{5}+2-\frac{-11}{9}-\frac{-3}{2}$$
$$\frac{1}{5}+\frac{10}{5}-\frac{-11}{9}-\frac{-3}{2}$$
$$\frac{1+10}{5}-\frac{-11}{9}-\frac{-3}{2}$$
$$\frac{11}{5}-\frac{-11}{9}-\frac{-3}{2}$$
$$\frac{11}{5}-\left(-\frac{11}{9}\right)-\frac{-3}{2}$$
$$\frac{11}{5}+\frac{11}{9}-\frac{-3}{2}$$
$$\frac{99}{45}+\frac{55}{45}-\frac{-3}{2}$$
$$\frac{99+55}{45}-\frac{-3}{2}$$
$$\frac{154}{45}-\frac{-3}{2}$$
$$\frac{154}{45}-\left(-\frac{3}{2}\right)$$
$$\frac{154}{45}+\frac{3}{2}$$
$$\frac{308}{90}+\frac{135}{90}$$
$$\frac{308+135}{90}$$
$$\frac{443}{90}$$
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$\frac{443}{2 \cdot 3 ^ {2} \cdot 5} = 4\frac{83}{90} = 4.9222222222222225$