Question

$$(\frac{215}{418})^{2}\times(\frac{418}{215})^{2}+\frac{3^{3}\times4^{3}}{12^{3}}\cdot$$

Answer

$$8.1163952846759*10^21+27*4^312^3*$$

Solution


Simplify  \({215418}^{2}\)  to  \(46404914724\).
\[46404914724\times {418215}^{2}+{3}^{3}\times {4}^{{312}^{3}}\]
Simplify  \({418215}^{2}\)  to  \(174903786225\).
\[46404914724\times 174903786225+{3}^{3}\times {4}^{{312}^{3}}\]
Simplify  \({3}^{3}\)  to  \(27\).
\[46404914724\times 174903786225+27\times {4}^{{312}^{3}}\]
Simplify  \(46404914724\times 174903786225\)  to  \(8.116395\times {10}^{21}\).
\[8.116395\times {10}^{21}+27\times {4}^{{312}^{3}}\]