$$(\frac{2x-1}{3})+(\frac{6x-2}{5})=\frac{1}{3}$$
$x=\frac{4}{7}\approx 0.571428571$
$$5\left(2x-1\right)+3\left(6x-2\right)=5$$
$$10x-5+3\left(6x-2\right)=5$$
$$10x-5+18x-6=5$$
$$28x-5-6=5$$
$$28x-11=5$$
$$28x=5+11$$
$$28x=16$$
$$x=\frac{16}{28}$$
$$x=\frac{4}{7}$$
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