How to solve [(3/2) ^ 4] ^ - 8

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve [(3/2) ^ 4] ^ - 8 | Equatix

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$$[(\frac{3}{2})^{4}]^{-8}$$

$\frac{4294967296}{1853020188851841}\approx 0.000002318$

Use the rules of exponents to simplify the expression.

$$\left(\left(\frac{3}{2}\right)^{4}\right)^{-8}$$

To raise a power to another power, multiply the exponents.

$$\left(\frac{3}{2}\right)^{4\left(-8\right)}$$

Multiply $4$ times $-8$.

$$\left(\frac{3}{2}\right)^{-32}$$

Raise $\frac{3}{2}$ to the power $-32$.

$$\frac{4294967296}{1853020188851841}$$

$\frac{2 ^ {32}}{3 ^ {32}} = 2.3178200225984726 \times 10^{-6}$