Question

$$(\frac{3}{4})^{2}\times(\frac{3}{4})^{5}\div(\frac{3}{4})^{6}\div\frac{7}{8}\times(\frac{8}{7}\div\frac{4}{6})\times\frac{6}{7}\times\frac{7}{6}+\frac{1}{2}\times$$

Answer

1255178/299+12*

Solution


Use this rule: \(\frac{a}{b} \times \frac{c}{d}=\frac{ac}{bd}\).
\[\frac{{34}^{2}\times {34}^{5}\times 87\times 67\times 76}{{34}^{6}\times 78\times 46}+12\]
Simplify  \({34}^{2}\times {34}^{5}\)  to  \({34}^{7}\).
\[\frac{{34}^{7}\times 87\times 67\times 76}{{34}^{6}\times 78\times 46}+12\]
Simplify  \({34}^{7}\times 87\times 67\times 76\)  to  \(443004\times {34}^{7}\).
\[\frac{443004\times {34}^{7}}{{34}^{6}\times 78\times 46}+12\]
Simplify  \({34}^{6}\times 78\times 46\)  to  \(3588\times {34}^{6}\).
\[\frac{443004\times {34}^{7}}{3588\times {34}^{6}}+12\]
Use Quotient Rule: \(\frac{{x}^{a}}{{x}^{b}}={x}^{a-b}\).
\[443004\times {34}^{7-6}\times {3588}^{-1}+12\]
Simplify  \(7-6\)  to  \(1\).
\[443004\times {34}^{1}\times {3588}^{-1}+12\]
Use Rule of One: \({x}^{1}=x\).
\[443004\times 34\times {3588}^{-1}+12\]
Use Negative Power Rule: \({x}^{-a}=\frac{1}{{x}^{a}}\).
\[443004\times 34\times \frac{1}{3588}+12\]
Use this rule: \(\frac{a}{b} \times \frac{c}{d}=\frac{ac}{bd}\).
\[\frac{443004\times 34\times 1}{3588}+12\]
Simplify  \(443004\times 34\)  to  \(15062136\).
\[\frac{15062136\times 1}{3588}+12\]
Simplify  \(15062136\times 1\)  to  \(15062136\).
\[\frac{15062136}{3588}+12\]
Simplify  \(\frac{15062136}{3588}\)  to  \(\frac{1255178}{299}\).
\[\frac{1255178}{299}+12\]