$$(\frac{3}{4})^{-1}+(\frac{3}{2})^{2}$$
$\frac{43}{12}\approx 3.583333333$
$$\frac{4}{3}+\left(\frac{3}{2}\right)^{2}$$
$$\frac{4}{3}+\frac{9}{4}$$
$$\frac{43}{12}$$
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$\frac{43}{2 ^ {2} \cdot 3} = 3\frac{7}{12} = 3.5833333333333335$
