$$(\frac{3}{4})^{-9}\times(\frac{3}{4})^{-7}=(\frac{3}{4})^{4x}$$
$x=-4$
$x=\frac{\pi n_{1}i}{2\ln(\frac{3}{4})}-\frac{\log_{\frac{3}{4}}\left(\frac{6561}{65536}\right)}{2}$
$n_{1}\in \mathrm{Z}$
