Use Negative Power Rule: \({x}^{-a}=\frac{1}{{x}^{a}}\).
\[{35}^{3}\times \frac{1}{{35}^{6}}={35}^{2}x-1-\]
Simplify \({35}^{3}\) to \(42875\).
\[42875\times \frac{1}{{35}^{6}}={35}^{2}x-1-\]
Simplify \({35}^{2}\) to \(1225\).
\[42875\times \frac{1}{{35}^{6}}=1225x-1-\]
Simplify \(42875\times \frac{1}{{35}^{6}}\) to \(\frac{42875}{{35}^{6}}\).
\[\frac{42875}{{35}^{6}}=1225x-1-\]
Add \(1-\) to both sides.
\[\frac{42875}{{35}^{6}}+1-=1225x\]
Divide both sides by \(1225\).
\[\frac{\frac{42875}{{35}^{6}}+1-}{1225}=x\]
Simplify \(\frac{\frac{42875}{{35}^{6}}+1-}{1225}\) to \(\frac{\frac{42875}{{35}^{6}}}{1225}+\frac{1-}{1225}\).
\[\frac{\frac{42875}{{35}^{6}}}{1225}+\frac{1-}{1225}=x\]
Simplify \(\frac{\frac{42875}{{35}^{6}}}{1225}\) to \(\frac{42875}{{35}^{6}\times 1225}\).
\[\frac{42875}{{35}^{6}\times 1225}+\frac{1-}{1225}=x\]
Switch sides.
\[x=\frac{42875}{{35}^{6}\times 1225}+\frac{1-}{1225}\]
x=42875/(35^6*1225)+(1-)/1225
