$$(\frac{3}{7}\times\frac{4}{9})\times(\frac{-7}{12})=\frac{3}{7}\times[\frac{4}{9}\times(\frac{-7}{12})]$$
$\text{true}$
$$\frac{-7}{12}=\frac{-7}{12}$$
$$-\frac{7}{12}=\frac{-7}{12}$$
$$-\frac{7}{12}=-\frac{7}{12}$$
$$\text{true}$$
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