How to solve 36 21 42 6

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 36 21 42 6 | Equatix

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$$( \frac { 36 } { 42 } ) \times ( \frac { 21 } { 6 } )$$

$3$

Reduce the fraction $\frac{36}{42}$ to lowest terms by extracting and canceling out $6$.

$$\frac{6}{7}\times \frac{21}{6}$$

Reduce the fraction $\frac{21}{6}$ to lowest terms by extracting and canceling out $3$.

$$\frac{6}{7}\times \frac{7}{2}$$

Multiply $\frac{6}{7}$ times $\frac{7}{2}$ by multiplying numerator times numerator and denominator times denominator.

$$\frac{6\times 7}{7\times 2}$$

Cancel out $7$ in both numerator and denominator.

$$\frac{6}{2}$$

Divide $6$ by $2$ to get $3$.

$$3$$

$3$