$$(\frac{4}{7}+\frac{1}{6})+1\frac{2}{3}$$
$\frac{101}{42}\approx 2.404761905$
$$\frac{24}{42}+\frac{7}{42}+\frac{1\times 3+2}{3}$$
$$\frac{24+7}{42}+\frac{1\times 3+2}{3}$$
$$\frac{31}{42}+\frac{1\times 3+2}{3}$$
$$\frac{31}{42}+\frac{3+2}{3}$$
$$\frac{31}{42}+\frac{5}{3}$$
$$\frac{31}{42}+\frac{70}{42}$$
$$\frac{31+70}{42}$$
$$\frac{101}{42}$$
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$\frac{101}{2 \cdot 3 \cdot 7} = 2\frac{17}{42} = 2.4047619047619047$
