$$( \frac { 4 } { 9 } - \frac { 3 } { 11 } ) \times ( 2 \frac { 3 } { 4 } + 3 \frac { 2 } { 3 } )$$
$\frac{119}{108}\approx 1.101851852$
$$\left(\frac{44}{99}-\frac{27}{99}\right)\left(\frac{2\times 4+3}{4}+\frac{3\times 3+2}{3}\right)$$
$$\frac{44-27}{99}\left(\frac{2\times 4+3}{4}+\frac{3\times 3+2}{3}\right)$$
$$\frac{17}{99}\left(\frac{2\times 4+3}{4}+\frac{3\times 3+2}{3}\right)$$
$$\frac{17}{99}\left(\frac{8+3}{4}+\frac{3\times 3+2}{3}\right)$$
$$\frac{17}{99}\left(\frac{11}{4}+\frac{3\times 3+2}{3}\right)$$
$$\frac{17}{99}\left(\frac{11}{4}+\frac{9+2}{3}\right)$$
$$\frac{17}{99}\left(\frac{11}{4}+\frac{11}{3}\right)$$
$$\frac{17}{99}\left(\frac{33}{12}+\frac{44}{12}\right)$$
$$\frac{17}{99}\times \frac{33+44}{12}$$
$$\frac{17}{99}\times \frac{77}{12}$$
$$\frac{17\times 77}{99\times 12}$$
$$\frac{1309}{1188}$$
$$\frac{119}{108}$$
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$\frac{7 \cdot 17}{2 ^ {2} \cdot 3 ^ {3}} = 1\frac{11}{108} = 1.1018518518518519$
