$$(\frac{4}{9})^{4}\div(\frac{16}{27})^{2}$$
$\frac{1}{9}\approx 0.111111111$
$$\frac{\frac{256}{6561}}{\left(\frac{16}{27}\right)^{2}}$$
$$\frac{\frac{256}{6561}}{\frac{256}{729}}$$
$$\frac{256}{6561}\times \frac{729}{256}$$
$$\frac{256\times 729}{6561\times 256}$$
$$\frac{729}{6561}$$
$$\frac{1}{9}$$
Show Solution
Hide Solution
$\frac{1}{3 ^ {2}} = 0.1111111111111111$
