$$(\frac{6}{3})^{2}+(\frac{7}{4})^{2}$$
$\frac{113}{16}=7.0625$
$$2^{2}+\left(\frac{7}{4}\right)^{2}$$
$$4+\left(\frac{7}{4}\right)^{2}$$
$$4+\frac{49}{16}$$
$$\frac{113}{16}$$
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$\frac{113}{2 ^ {4}} = 7\frac{1}{16} = 7.0625$
