How to solve (6/7 + 3/2)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (6/7 + 3/2) | Equatix

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$$(\frac{6}{7}+\frac{3}{2})$$

$\frac{33}{14}\approx 2.357142857$

Least common multiple of $7$ and $2$ is $14$. Convert $\frac{6}{7}$ and $\frac{3}{2}$ to fractions with denominator $14$.

$$\frac{12}{14}+\frac{21}{14}$$

Since $\frac{12}{14}$ and $\frac{21}{14}$ have the same denominator, add them by adding their numerators.

$$\frac{12+21}{14}$$

Add $12$ and $21$ to get $33$.

$$\frac{33}{14}$$

$\frac{3 \cdot 11}{2 \cdot 7} = 2\frac{5}{14} = 2.357142857142857$