How to solve 7 5 5 2 3

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 7 5 5 2 3 | Equatix

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Question

$$( \frac { 7 } { 5 } + \frac { 3 } { 2 } ) \div ( \frac { 5 } { 2 } + \frac { 1 } { 3 } )$$

Evaluate

$\frac{87}{85}\approx 1.023529412$

Solution Steps

Least common multiple of $5$ and $2$ is $10$. Convert $\frac{7}{5}$ and $\frac{3}{2}$ to fractions with denominator $10$.

$$\frac{\frac{14}{10}+\frac{15}{10}}{\frac{5}{2}+\frac{1}{3}}$$

Since $\frac{14}{10}$ and $\frac{15}{10}$ have the same denominator, add them by adding their numerators.

$$\frac{\frac{14+15}{10}}{\frac{5}{2}+\frac{1}{3}}$$

Add $14$ and $15$ to get $29$.

$$\frac{\frac{29}{10}}{\frac{5}{2}+\frac{1}{3}}$$

Least common multiple of $2$ and $3$ is $6$. Convert $\frac{5}{2}$ and $\frac{1}{3}$ to fractions with denominator $6$.

$$\frac{\frac{29}{10}}{\frac{15}{6}+\frac{2}{6}}$$

Since $\frac{15}{6}$ and $\frac{2}{6}$ have the same denominator, add them by adding their numerators.

$$\frac{\frac{29}{10}}{\frac{15+2}{6}}$$

Add $15$ and $2$ to get $17$.

$$\frac{\frac{29}{10}}{\frac{17}{6}}$$

Divide $\frac{29}{10}$ by $\frac{17}{6}$ by multiplying $\frac{29}{10}$ by the reciprocal of $\frac{17}{6}$.

$$\frac{29}{10}\times \frac{6}{17}$$

Multiply $\frac{29}{10}$ times $\frac{6}{17}$ by multiplying numerator times numerator and denominator times denominator.

$$\frac{29\times 6}{10\times 17}$$

Do the multiplications in the fraction $\frac{29\times 6}{10\times 17}$.

$$\frac{174}{170}$$

Reduce the fraction $\frac{174}{170}$ to lowest terms by extracting and canceling out $2$.

$$\frac{87}{85}$$

Show Solution

Factor

$\frac{3 \cdot 29}{5 \cdot 17} = 1\frac{2}{85} = 1.0235294117647058$