$$(\frac{7}{9}\times\frac{19}{5})-(\frac{7}{9}\times\frac{4}{5})$$
$\frac{7}{3}\approx 2.333333333$
$$\frac{7\times 19}{9\times 5}-\frac{7}{9}\times \frac{4}{5}$$
$$\frac{133}{45}-\frac{7}{9}\times \frac{4}{5}$$
$$\frac{133}{45}-\frac{7\times 4}{9\times 5}$$
$$\frac{133}{45}-\frac{28}{45}$$
$$\frac{133-28}{45}$$
$$\frac{105}{45}$$
$$\frac{7}{3}$$
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$\frac{7}{3} = 2\frac{1}{3} = 2.3333333333333335$
