Divide $\frac{\left(a^{4}y^{-2}\right)^{-3}}{\left(b^{4}x^{-1}\right)^{-3}}$ by $\frac{\left(a^{-2}b^{4}\right)^{9}}{\left(x^{-3}y^{4}\right)^{9}}$ by multiplying $\frac{\left(a^{4}y^{-2}\right)^{-3}}{\left(b^{4}x^{-1}\right)^{-3}}$ by the reciprocal of $\frac{\left(a^{-2}b^{4}\right)^{9}}{\left(x^{-3}y^{4}\right)^{9}}$.
Divide $\frac{\left(a^{4}y^{-2}\right)^{-3}}{\left(b^{4}x^{-1}\right)^{-3}}$ by $\frac{\left(a^{-2}b^{4}\right)^{9}}{\left(x^{-3}y^{4}\right)^{9}}$ by multiplying $\frac{\left(a^{4}y^{-2}\right)^{-3}}{\left(b^{4}x^{-1}\right)^{-3}}$ by the reciprocal of $\frac{\left(a^{-2}b^{4}\right)^{9}}{\left(x^{-3}y^{4}\right)^{9}}$.