$$(\frac{k-5}{h-6})(\frac{-3-k}{2-h})=-1$$
$h=\sqrt{19+2k-k^{2}}+4$
$h=-\sqrt{19+2k-k^{2}}+4\text{, }k\neq -3\text{ and }k\neq 5$
$k=-\sqrt{4+8h-h^{2}}+1$
$k=\sqrt{4+8h-h^{2}}+1\text{, }h\neq 6\text{ and }h\neq 2$
$h=\sqrt{19+2k-k^{2}}+4$
$h=-\sqrt{19+2k-k^{2}}+4\text{, }k\geq 1-2\sqrt{5}\text{ and }k\leq 2\sqrt{5}+1\text{ and }k\neq -3\text{ and }k\neq 5$
$k=-\sqrt{4+8h-h^{2}}+1$
$k=\sqrt{4+8h-h^{2}}+1\text{, }h\geq 4-2\sqrt{5}\text{ and }h\leq 2\sqrt{5}+4\text{ and }h\neq 6\text{ and }h\neq 2$