Solve (- 1/4 - (- 1/3)] = (- 1/4 - 1/3) | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(\frac{-1}{4}-(\frac{-1}{3})]=(\frac{-1}{4}-\frac{1}{3})$$

Verify

$\text{false}$

Solution Steps

Fraction $\frac{-1}{4}$ can be rewritten as $-\frac{1}{4}$ by extracting the negative sign.

$$-\frac{1}{4}-\frac{-1}{3}=\frac{-1}{4}-\frac{1}{3}$$

Fraction $\frac{-1}{3}$ can be rewritten as $-\frac{1}{3}$ by extracting the negative sign.

$$-\frac{1}{4}-\left(-\frac{1}{3}\right)=\frac{-1}{4}-\frac{1}{3}$$

The opposite of $-\frac{1}{3}$ is $\frac{1}{3}$.

$$-\frac{1}{4}+\frac{1}{3}=\frac{-1}{4}-\frac{1}{3}$$

Least common multiple of $4$ and $3$ is $12$. Convert $-\frac{1}{4}$ and $\frac{1}{3}$ to fractions with denominator $12$.

$$-\frac{3}{12}+\frac{4}{12}=\frac{-1}{4}-\frac{1}{3}$$

Since $-\frac{3}{12}$ and $\frac{4}{12}$ have the same denominator, add them by adding their numerators.

$$\frac{-3+4}{12}=\frac{-1}{4}-\frac{1}{3}$$

Add $-3$ and $4$ to get $1$.

$$\frac{1}{12}=\frac{-1}{4}-\frac{1}{3}$$

Fraction $\frac{-1}{4}$ can be rewritten as $-\frac{1}{4}$ by extracting the negative sign.

$$\frac{1}{12}=-\frac{1}{4}-\frac{1}{3}$$

Least common multiple of $4$ and $3$ is $12$. Convert $-\frac{1}{4}$ and $\frac{1}{3}$ to fractions with denominator $12$.

$$\frac{1}{12}=-\frac{3}{12}-\frac{4}{12}$$

Since $-\frac{3}{12}$ and $\frac{4}{12}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{1}{12}=\frac{-3-4}{12}$$

Subtract $4$ from $-3$ to get $-7$.

$$\frac{1}{12}=-\frac{7}{12}$$

Compare $\frac{1}{12}$ and $-\frac{7}{12}$.

$$\text{false}$$