How to solve (- 2/3)(- 6/8)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (- 2/3)(- 6/8) | Equatix

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

$$(\frac{-2}{3})\times(\frac{-6}{8})$$

$\frac{1}{2}=0.5$

Fraction $\frac{-2}{3}$ can be rewritten as $-\frac{2}{3}$ by extracting the negative sign.

$$-\frac{2}{3}\times \frac{-6}{8}$$

Reduce the fraction $\frac{-6}{8}$ to lowest terms by extracting and canceling out $2$.

$$-\frac{2}{3}\left(-\frac{3}{4}\right)$$

Multiply $-\frac{2}{3}$ times $-\frac{3}{4}$ by multiplying numerator times numerator and denominator times denominator.

$$\frac{-2\left(-3\right)}{3\times 4}$$

Do the multiplications in the fraction $\frac{-2\left(-3\right)}{3\times 4}$.

$$\frac{6}{12}$$

Reduce the fraction $\frac{6}{12}$ to lowest terms by extracting and canceling out $6$.

$$\frac{1}{2}$$

$\frac{1}{2} = 0.5$