Divide $\frac{\left(-2x^{2}z^{3}\right)^{2}}{\left(a^{2}\right)^{2}}$ by $\frac{\left(2a^{2}y^{2}\right)^{-3}}{\left(x^{-2}\right)^{-3}}$ by multiplying $\frac{\left(-2x^{2}z^{3}\right)^{2}}{\left(a^{2}\right)^{2}}$ by the reciprocal of $\frac{\left(2a^{2}y^{2}\right)^{-3}}{\left(x^{-2}\right)^{-3}}$.
Divide $\frac{\left(-2x^{2}z^{3}\right)^{2}}{\left(a^{2}\right)^{2}}$ by $\frac{\left(2a^{2}y^{2}\right)^{-3}}{\left(x^{-2}\right)^{-3}}$ by multiplying $\frac{\left(-2x^{2}z^{3}\right)^{2}}{\left(a^{2}\right)^{2}}$ by the reciprocal of $\frac{\left(2a^{2}y^{2}\right)^{-3}}{\left(x^{-2}\right)^{-3}}$.