$$(\frac{-20}{99}\times\frac{33}{4})\div(-\frac{12}{19})$$
$\frac{95}{36}\approx 2.638888889$
$$\frac{-\frac{20}{99}\times \frac{33}{4}}{-\frac{12}{19}}$$
$$\frac{\frac{-20\times 33}{99\times 4}}{-\frac{12}{19}}$$
$$\frac{\frac{-660}{396}}{-\frac{12}{19}}$$
$$\frac{-\frac{5}{3}}{-\frac{12}{19}}$$
$$-\frac{5}{3}\left(-\frac{19}{12}\right)$$
$$\frac{-5\left(-19\right)}{3\times 12}$$
$$\frac{95}{36}$$
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$\frac{5 \cdot 19}{2 ^ {2} \cdot 3 ^ {2}} = 2\frac{23}{36} = 2.638888888888889$
