Solve Commutative ( -3 4 )+3=3+( -3 4 )=.Paneit | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$( \frac { - 3 } { 4 } ) + 3 = 3 + ( \frac { - 3 } { 4 } ) =$$

Verify

$\text{true}$

Solution Steps

Fraction $\frac{-3}{4}$ can be rewritten as $-\frac{3}{4}$ by extracting the negative sign.

$$-\frac{3}{4}+3=3+\frac{-3}{4}$$

Convert $3$ to fraction $\frac{12}{4}$.

$$-\frac{3}{4}+\frac{12}{4}=3+\frac{-3}{4}$$

Since $-\frac{3}{4}$ and $\frac{12}{4}$ have the same denominator, add them by adding their numerators.

$$\frac{-3+12}{4}=3+\frac{-3}{4}$$

Add $-3$ and $12$ to get $9$.

$$\frac{9}{4}=3+\frac{-3}{4}$$

Fraction $\frac{-3}{4}$ can be rewritten as $-\frac{3}{4}$ by extracting the negative sign.

$$\frac{9}{4}=3-\frac{3}{4}$$

Convert $3$ to fraction $\frac{12}{4}$.

$$\frac{9}{4}=\frac{12}{4}-\frac{3}{4}$$

Since $\frac{12}{4}$ and $\frac{3}{4}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{9}{4}=\frac{12-3}{4}$$

Subtract $3$ from $12$ to get $9$.

$$\frac{9}{4}=\frac{9}{4}$$

Compare $\frac{9}{4}$ and $\frac{9}{4}$.

$$\text{true}$$