$$( \frac{ -3 }{ 4 } + \frac{ 5 }{ -4 } )+( \frac{ -4 }{ 5 } + \frac{ 4 }{ -5 } )$$
$-\frac{18}{5}=-3.6$
$$-\frac{3}{4}+\frac{5}{-4}+\frac{-4}{5}+\frac{4}{-5}$$
$$-\frac{3}{4}-\frac{5}{4}+\frac{-4}{5}+\frac{4}{-5}$$
$$\frac{-3-5}{4}+\frac{-4}{5}+\frac{4}{-5}$$
$$\frac{-8}{4}+\frac{-4}{5}+\frac{4}{-5}$$
$$-2+\frac{-4}{5}+\frac{4}{-5}$$
$$-2-\frac{4}{5}+\frac{4}{-5}$$
$$-\frac{10}{5}-\frac{4}{5}+\frac{4}{-5}$$
$$\frac{-10-4}{5}+\frac{4}{-5}$$
$$-\frac{14}{5}+\frac{4}{-5}$$
$$-\frac{14}{5}-\frac{4}{5}$$
$$\frac{-14-4}{5}$$
$$-\frac{18}{5}$$
Show Solution
Hide Solution
$-\frac{18}{5} = -3\frac{3}{5} = -3.6$
