Question

$$( \frac{ x-3 }{ 5 } )+( \frac{ x-4 }{ 9 } )=6-( \frac{ 2x-1 }{ 45 } )$$

Answer

x=159/8

Solution


Remove parentheses.
\[\frac{x-3}{5}+\frac{x-4}{9}=6-\frac{2x-1}{45}\]
Multiply both sides by \(45\) (the LCM of \(5, 9, 45\)).
\[9(x-3)+5(x-4)=270-2x+1\]
Simplify  \(270-2x+1\)  to  \(-2x+271\).
\[9(x-3)+5(x-4)=-2x+271\]
Expand.
\[9x-27+5x-20=-2x+271\]
Simplify  \(9x-27+5x-20\)  to  \(14x-47\).
\[14x-47=-2x+271\]
Add \(47\) to both sides.
\[14x=-2x+271+47\]
Simplify  \(-2x+271+47\)  to  \(-2x+318\).
\[14x=-2x+318\]
Add \(2x\) to both sides.
\[14x+2x=318\]
Simplify  \(14x+2x\)  to  \(16x\).
\[16x=318\]
Divide both sides by \(16\).
\[x=\frac{318}{16}\]
Simplify  \(\frac{318}{16}\)  to  \(\frac{159}{8}\).
\[x=\frac{159}{8}\]

Decimal Form: 19.875