$$( \frac { x ^ { - 2 } } { 3 y ^ { - 1 } } ) ^ { - 1 }$$
$\frac{3x^{2}}{y}$
$$\frac{\left(x^{-2}\right)^{-1}}{\left(3y^{-1}\right)^{-1}}$$
$$\frac{x^{2}}{\left(3y^{-1}\right)^{-1}}$$
$$\frac{x^{2}}{3^{-1}\left(y^{-1}\right)^{-1}}$$
$$\frac{x^{2}}{3^{-1}y^{1}}$$
$$\frac{x^{2}}{\frac{1}{3}y^{1}}$$
$$\frac{x^{2}}{\frac{1}{3}y}$$
Show Solution
Hide Solution
$\frac{6x}{y}$